VB知识库

常微分方程(x-2xy-y^2)dy+y^2dx=0通解是什么解：∵(x-2xy-y^2)dy+y^2dx=0==>x(1-2y)dy+y^2dx=y^2dy==>x(1-2y)e^(-1y)dyy^4+e^(-1y)dxy^2=e^(-1y)dyy^2(等式两端同乘e^(-1y)y^4)==>xd(e^(-1y)y^2)+e^(-1y)d …